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Sets, Relations and Function - JEE Mathematics question (JEE Main 2023 (Online) 6th April Morning Shift)

JEE Main 2023 (Online) 6th April Morning ShiftQuestion 1
Let $A=\{x\in\mathbb{R}:[x+3]+[x+4]\le3\}$, $B=\left\{x\in\mathbb{R}:3^{x}\left(\sum_{r=1}^{\infty}\frac{3}{10^{r}}\right)^{x-3}<3^{-3x}\right\}$, where $[t]$ denotes greatest integer function. Then,
Sets, Relations and Function
Options for question 1, choose one

Solution

$[x+3]+[x+4]=2[x]+7\le3\Rightarrow[x]\le-2\Rightarrow x<-1$. $\sum 3/10^r=1/3$, so $3^x\cdot3^{-(x-3)}=27<3^{-3x}\Rightarrow -3x>3\Rightarrow x<-1$. $A=B$. Option (A).

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