JEE Main 2021 (Online) 3rd August Evening ShiftQuestion 1
Let $\mathbb{R}$ be the set of real numbers and '$*$' be a binary operation on $\mathbb{R}-\{0\}$ defined by $a*b=a+2b+\frac{a}{b}$. Then the operation '$*$' is
Sets, Relations and Function
Solution
$1*2=1+4+\tfrac12=5.5$ but $2*1=2+2+2=6$, so not commutative. $(1*1)*1=4*1=10$ but $1*(1*1)=1*4=9.25$, so not associative. Option (D).