JEE Main 2016 (Offline)Question 1
The Boolean expression $(p\wedge\sim q)\vee q\vee(\sim p\wedge q)$ is equivalent to
Sets, Relations and Function
Solution
$(p\wedge\sim q)\vee q=(p\vee q)\wedge(\sim q\vee q)=p\vee q$, and adding $\sim p\wedge q$ (which implies $q$) changes nothing: $p\vee q$.