JEE Main 2021 (Online) 26th August Evening ShiftQuestion 1
A fair die is tossed until six is obtained on it. Let $X$ be the number of required tosses, then the conditional probability $P(X\ge5\mid X>2)$ is :
Probability
Solution
$P(X>n)=(5/6)^n$. $P(X\ge5\mid X>2)=\frac{P(X>4)}{P(X>2)}=(5/6)^2=\frac{25}{36}$. Option B.