JEE Advanced 2013 Paper 2Question 1
If chord $PQ$ subtends an angle $\theta$ at the vertex of $y^2=4ax$, then $\tan\theta=$
Parabola
Solution
Take $a=1$: $x_1x_2=1$, $y_1y_2=-4$, $|y_1-y_2|=2\sqrt5$ (from $x_{1,2}=\frac{3\pm\sqrt5}{2}$). $\vec{OP}\cdot\vec{OQ}=1-4=-3<0$ so $\theta$ is obtuse, and slopes $m=4/y$ give $\tan\theta=\frac{m_1-m_2}{1+m_1m_2}=\frac{\pm2\sqrt5}{-3}$; with $\theta$ obtuse, $\tan\theta=-\frac23\sqrt5$.