JEE Main 2024 (Online) 9th April Evening ShiftQuestion 1
$\lim_{x\to0}\frac{e-(1+2x)^{\frac{1}{2x}}}{x}$ is equal to
Limits & Continuity
Solution
$(1+2x)^{1/(2x)}=\exp\left(\frac{\ln(1+2x)}{2x}\right)$ and $\frac{\ln(1+2x)}{2x}=1-x+O(x^2)$. So $(1+2x)^{1/(2x)}=e(1-x+O(x^2))$ and $e-(\cdot)=ex+O(x^2)$. Limit $=e$. Option (A).