JEE Main 2021 (Online) 25th July Evening ShiftQuestion 1
The lowest integer which is greater than $\left(1+\frac{1}{10^{100}}\right)^{10^{100}}$ is :
Limits & Continuity
Solution
$\left(1+\frac1N\right)^N$ is increasing with limit $e$, so $2<\left(1+\frac1N\right)^N<e<3$ for $N=10^{100}$. Lowest integer greater than it is $3$: option C.