JEE Main 2015 (Online) 10th AprilQuestion 1
If $f(x)=2\tan^{-1}x+\sin^{-1}\left(\frac{2x}{1+x^2}\right)$, $x>1$, then $f(5)$ is equal to
Inverse Trigonometric Functions
Solution
For $x>1$, $\sin^{-1}\frac{2x}{1+x^2}=\pi-2\tan^{-1}x$, so $f(x)=\pi$ and $f(5)=\pi$.