Ellipse: The equation of the chord, of the ellipse dfracx^225+dfracy^216=1 ,… | JEE Main 2025 | Yukti Vault

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JEE Main 2025 (Online) 24th January Evening ShiftQuestion 1

The equation of the chord, of the ellipse $\dfrac{x^{2}}{25}+\dfrac{y^{2}}{16}=1$, whose mid-point is $(3,1)$ is :

Ellipse

$5x+16y=31$$48x+25y=169$✓ Correct answer$4x+122y=134$$25x+101y=176$

Solution

$T=S_1$: $\frac{3x}{25}+\frac y{16}=\frac9{25}+\frac1{16}$, i.e. $48x+25y=169$.

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