JEE Main 2015 (Online) 10th AprilQuestion 1
The area (in square units) of the region bounded by the curves $y+2x^2=0$ and $y+3x^2=1$, is equal to
Application of Integrals
Solution
$-2x^2=1-3x^2\Rightarrow x=\pm1$. Area $=\int_{-1}^{1}(1-x^2)dx=\frac43$.