JEE Main 2024 (Online) 6th April Morning ShiftQuestion 1
If $A(3,1,-1)$, $B\left(\frac{5}{3},\frac{7}{3},\frac{1}{3}\right)$, $C(2,2,1)$ and $D\left(\frac{10}{3},\frac{2}{3},\frac{-1}{3}\right)$ are the vertices of a quadrilateral $ABCD$, then its area is
3D Geometry
Solution
Points are coplanar; area $=\frac12|\vec{AC}\times\vec{BD}|$ with $\vec{AC}=(-1,1,2)$, $\vec{BD}=(\frac53,-\frac53,-\frac23)$, cross $=(\frac83,\frac83,0)$. Area $=\frac12\cdot\frac{8\sqrt2}3=\frac{4\sqrt2}3$.