JEE Advanced 2021 Paper 1Question 1
The value of $D$ is ___ .
3D Geometry
Answer$1.5$
Solution
Consistency needs $R_1-2R_2+R_3$ to vanish on the left: $\alpha-2\beta+\gamma-1=0$. This is plane $P$. Distance of $(0,1,0)$ is $|-2-1|/\sqrt6$, so $D=9/6=1.5$.