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Yukti Vault

3D Geometry - JEE Mathematics question (AIEEE 2011 (Offline))

AIEEE 2011 (Offline)Question 1
If the angle between the line $x=\frac{y-1}{2}=\frac{z-3}{\lambda}$ and the plane $x+2y+3z=4$ is $\cos^{-1}\left(\sqrt{\frac{5}{14}}\right)$, then $\lambda$ equals :
3D Geometry
Options for question 1, choose one

Solution

$\cos\theta=\sqrt{\frac5{14}}\Rightarrow\sin\theta=\frac3{\sqrt{14}}=\frac{|1+4+3\lambda|}{\sqrt{5+\lambda^2}\sqrt{14}}$, so $(5+3\lambda)^2=9(5+\lambda^2)$, $\lambda=\frac23$.

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