JEE Main 2021 (Online) 20th July Evening ShiftQuestion 7516
For $k\in\mathbf{N}$, let $\dfrac{1}{\alpha(\alpha+1)(\alpha+2)\cdots(\alpha+20)}=\displaystyle\sum_{k=0}^{20}\dfrac{A_k}{\alpha+k}$, where $\alpha>0$. Then the value of $100\left(\dfrac{A_{14}+A_{15}}{A_{13}}\right)^2$ is equal to $\_\_\_\_\_\_\_\_$ .
Sequence and Series · Miscellaneous