JEE Maths PYQ Practice, chapter-wise

JEE Main 2026 (Online) 5th April Evening ShiftQuestion 1

If the distance of the point $(a,2,5)$ from the image of the point $(1,2,7)$ in the line $\frac{x}{1}=\frac{y-1}{1}=\frac{z-2}{2}$ is $4$, then the sum of all possible values of $a$ is equal to :

3D Geometry

$11$$9$$6$$4$

JEE Main 2026 (Online) 4th April Evening ShiftQuestion 2

If $\left(2\alpha+1,\alpha^{2}-3\alpha,\frac{\alpha-1}{2}\right)$ is the image of $(\alpha,2\alpha,1)$ in the line $\frac{x-2}{3}=\frac{y-1}{2}=\frac{z}{1}$, then the possible value(s) of $\alpha$ is (are)

3D Geometry

Only $3$Only $3$ and $-1$Only $3,\frac{1}{4}$ and $-1$Only $3$ and $\frac{1}{4}$

JEE Main 2021 (Online) 24th February Morning ShiftQuestion 3

The equation of the plane passing through the point $(1,2,-3)$ and perpendicular to the planes $3x+y-2z=5$ and $2x-5y-z=7$, is :

3D Geometry

$6x-5y+2z+10=0$$11x+y+17z+38=0$$6x-5y-2z-2=0$$3x-10y-2z+11=0$

JEE Main 2026 (Online) 5th April Evening ShiftQuestion 4

Let a triangle $PQR$ be such that $P$ and $Q$ lie on the line $\frac{x+3}{8}=\frac{y-4}{2}=\frac{z+1}{2}$ and are at a distance of $6$ units from $R(1,2,3)$. If $(\alpha,\beta,\gamma)$ is the centroid of $\triangle PQR$, then $\alpha+\beta+\gamma$ is equal to :

3D Geometry

$4$$5$$6$$8$

JEE Main 2021 (Online) 24th February Morning ShiftQuestion 5

The distance of the point $(1,1,9)$ from the point of intersection of the line $\frac{x-3}{1}=\frac{y-4}{2}=\frac{z-5}{2}$ and the plane $x+y+z=17$ is :

3D Geometry

$2\sqrt{19}$$19\sqrt{2}$$\sqrt{38}$$38$